Something about the 2nd paragraph I need some clarification on:
This seems to squash my idea that the majority of sweetspot rotation takes place at the moment throw out action begins.
Is that right? Begin to rotate the clubface off the plane much sooner than throwout action and let centrifugal force just provide the "umph?" I thought throwout action was supposed to align for horizontal hinging? Somebody help!
In theory, yes, throwout should take care of it, but that assumes you are perfectly on plane and in Rhythm. By starting the process sooner, you are correct in that you are making sure that when throw out happens, all systems are 'go' (umph as you put it).
For a swinger, the best insurance is to understand that the left wrist uncocks and THEN the roll happens - a sequenced release. The roll being caused by the pivot and throw out.
If you have to 'try' too hard for that roll, chances are good you are either out of alignment (poor grip/setup) or off plane - both of which ultimately mean you are also out of the proper Rhythm.
__________________
"Support the On Plane Swinging Force in Balance"
"we have no friends, we have no enemies, we have only teachers"
Simplicity buffs, see 5-0, 1-L, 2-0 A and B 10-2-B, 4-D, 6B-1D, 6-B-3-0-1, 6-C-1, 6-E-2